[Agda] Equivalence axiom => extensionality
Thorsten Altenkirch
txa at Cs.Nott.AC.UK
Thu Jun 24 23:47:35 CEST 2010
I have played around a bit with weak equality trying to compare it
with isomorphism. In particular I tried to see what extra condition
weak equality corresponds to.
Given f : A → B and g : B → A we have
ε : (b : B) → f (g b) ≡ b
η : (a : A) → a ≡ g (f a)
which means that A and B are isomorphic.
I would expect that I get the equations corresponding to saying that ε
and η are an adjunction between groupoids (I think this was also what
Peter Lumsdaine suggested when he was in Nottingham):
α : ε (f a) ∘ f (η a) ≡ id
β : g (ε b) ∘ η (g b) ≡ id
However, when translating the condition corresponding to weak
equivalence I get: Given e : f a ≡ b
δ e : ε b ∘ f (g e ∘ η a) = e
Clearly the first equation is a consequence setting b = f a and e =
refl. But I don't see how the other equation would follow (and I don't
think there are interderivable).
Also I don't see that this enough in higher dimensions. Shouldn't we
expect equations relating α and β or δ?
An alternative would be to use equality of sets to express the
adjunction:
γ : (f a ≡ b) ≡ (a ≡ g b)
This may be a bit recursive (since we now define equality of sets via
equality of sets) but some progress seems to be happening since we are
now going one dimension up.
Cheers,
Thorsten
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