[Agda] syntax declaration
Ulf Norell
ulf.norell at gmail.com
Mon Mar 23 22:49:16 CET 2020
It should be
syntax exists A (λ x → P) = ex x ∶ A , P
/ Ulf
On Mon, Mar 23, 2020 at 10:13 PM Michel Levy <michel.levy.imag at free.fr>
wrote:
> Alas, the suggestion of Martin "syntax exists A P = ex x : A , P x"
> doesn't work.
>
> I still have the error : syntax must alternate holes and non-holes.
>
> And I get a lexical error when I replace the colon : by \:4
>
> I read
> "https://agda.readthedocs.io/en/v2.6.0/language/syntax-declarations.html"
> without finding the solution.
>
> Remark : I'm using agda version 2.5.3
>
> Le 23/03/2020 à 18:19, Martin Escardo a écrit :
> > Also you will need to write
> >
> > syntax exists A P = ex x : A , P x
> >
> > without the round brackets, I think.
> >
> > Martin
> >
> >
> > On 23/03/2020 17:18, Martin Escardo wrote:
> >> Use a different colon (:) symbol, such as the one you get by typing
> >> \:4 in emacs. I think the normal colon is reserved. Martin
> >>
> >> On 23/03/2020 16:53, michel.levy.imag at free.fr wrote:
> >>> I made the following statement
> >>>
> >>> data exists (A : Set)(P : A -> Set): Set where
> >>> <_,_> : (a : A) -> P a -> exists A P
> >>>
> >>> I would like to rewrite (exists A P) as, for example, (ex (x : A) P
> >>> x).
> >>> But I don't understand how to do it. I tried :
> >>>
> >>> syntax exists A P = ex (x : A) , P x
> >>>
> >>> but I had the mistake : syntax must use holes exactly once
> >>>
> >>> Can you explain to me how to use the syntax declaration on this
> >>> example ? What are these holes in my syntax statement ?
> >>>
> >>
> >
> --
> courriel : michel.levy.imag at free.fr
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> web : michel.levy.imag.free.fr
>
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