Please, how to prove the following? isHead : ℕ → List ℕ → Bool isHead _ [] = false isHead x (y ∷ ys) with x ≟ y ... | yes _ = true ... | no _ = false isHP : (x : ℕ) → (xs : List ℕ) → isHead x (x ∷ xs) ≡ true isHP x xs = ?? Thanks, ------ Sergei